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https://github.com/Sei-Lisa/LSL-PyOptimizer
synced 2025-07-01 23:58:20 +00:00
Add a bunch of optimizations. Fix || and && results.
Notably, addition/subtraction, and llGetListLength -> !=[] But also parenthesis removal etc. With test coverage.
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Sei Lisa
parent
0a567b0a39
commit
6ec39aa745
2 changed files with 237 additions and 35 deletions
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@ -39,6 +39,13 @@ class optimizer(object):
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if parent[index]['nt'] in ('CONST', 'IDENT', 'FIELD'):
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parent[index] = {'nt':';','t':None}
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def Cast(self, value, newtype):
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# Return a CAST node if the types are not equal, otherwise the
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# value unchanged
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if value['t'] == newtype:
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return value
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return {'nt':'CAST', 't':newtype, 'ch':[value]}
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def FoldTree(self, parent, index):
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"""Recursively traverse the tree to fold constants, changing it in
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place.
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@ -68,35 +75,53 @@ class optimizer(object):
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if nt == 'NEG':
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self.FoldTree(child, 0)
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if child[0]['nt'] == 'CONST':
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while child[0]['nt'] == '()' and child[0]['ch'][0]['nt'] == 'NEG':
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child[0] = child[0]['ch'][0] # Remove parentheses
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if child[0]['nt'] == 'NEG':
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# Double negation: - - expr
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parent[index] = child[0]['ch'][0]
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elif child[0]['nt'] == 'CONST':
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node = parent[index] = child[0]
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node['value'] = lslfuncs.neg(node['value'])
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return
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if nt == '!':
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self.FoldTree(child, 0)
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if child[0]['nt'] == 'CONST':
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node = parent[index] = child[0]
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# !! can *not* be simplified to !, but !!! can be simplified to !!
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subexpr = child[0]
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while subexpr['nt'] == '()' and subexpr['ch'][0]['nt'] in ('()', '~', '!', '++V', '--V'):
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subexpr = child[0] = subexpr['ch'][0] # Remove parentheses
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if subexpr['nt'] == '!' and subexpr['ch'][0]['nt'] == '!':
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# Simplify !!! to !
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subexpr = child[0] = subexpr['ch'][0]['ch'][0]
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if subexpr['nt'] == 'CONST':
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node = parent[index] = subexpr
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node['value'] = int(not node['value'])
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return
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if nt == '~':
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self.FoldTree(child, 0)
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if child[0]['nt'] == 'CONST':
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subexpr = child[0]
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while subexpr['nt'] == '()' and subexpr['ch'][0]['nt'] in ('()', '~', '!', '++V', '--V'):
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subexpr = child[0] = subexpr['ch'][0] # Remove parentheses
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if subexpr['nt'] == '~':
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# Double negation: ~~expr
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parent[index] = subexpr['ch'][0]
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elif subexpr['nt'] == 'CONST':
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node = parent[index] = child[0]
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node['value'] = ~node['value']
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return
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if nt == '()':
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self.FoldTree(child, 0)
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if child[0]['nt'] in ('CONST', 'VECTOR', 'ROTATION', 'LIST',
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if child[0]['nt'] in ('()', 'CONST', 'VECTOR', 'ROTATION', 'LIST',
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'IDENT', 'FIELD', 'V++', 'V--', 'FUNCTION', 'PRINT'):
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# Child is an unary postfix expression; parentheses are
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# redundant and can be removed safely. Not strictly an
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# optimization but it helps keep the output tidy-ish a bit.
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# It's not done in general (e.g. (a * b) + c does not need
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# parentheses but these are not eliminated). Only the cases
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# like (myvar) are simplified.
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# Child is an unary postfix expression (highest priority);
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# parentheses are redundant and can be removed safely. Not
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# strictly an optimization but it helps keeping the output
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# tidy-ish a bit. It's not done in general (e.g. (a * b) + c
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# does not need parentheses but these are not eliminated). Only
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# cases like (3) or (myvar++) are simplified.
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parent[index] = child[0]
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return
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@ -137,25 +162,163 @@ class optimizer(object):
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elif nt == '&':
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result = op1 & op2
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elif nt == '||':
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result = int(op1 or op2)
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result = int(bool(op1) or bool(op2))
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elif nt == '&&':
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result = int(op1 and op2)
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result = int(bool(op1) and bool(op2))
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else:
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raise Exception(u'Internal error: Operator not found: ' + nt.decode('utf8')) # pragma: no cover
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assert False, 'Internal error: Operator not found: ' + nt # pragma: no cover
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parent[index] = {'nt':'CONST', 't':node['t'], 'value':result}
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elif nt == '-' and child[0]['t'] in ('integer', 'float') \
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and child[1]['t'] in ('integer', 'float'):
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return
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# Simplifications for particular operands
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optype = node['t']
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lval = child[0]
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ltype = lval['t']
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lnt = lval['nt']
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rval = child[1]
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rtype = rval['t']
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rnt = rval['nt']
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if nt == '-':
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if optype in ('vector', 'rotation'):
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if lnt == 'CONST' and all(component == 0 for component in lval['value']):
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# Change <0,0,0[,0]>-expr -> -expr
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parent[index] = {'nt':'NEG', 't':node['t'], 'ch':[rval]}
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elif rnt == 'CONST' and all(component == 0 for component in rval['value']):
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# Change expr-<0,0,0[,0]> -> expr
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parent[index] = lval
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return
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# Change - to + - for int/float
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nt = node['nt'] = '+'
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if child[1]['nt'] == 'CONST':
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if child[1]['value'] == 0:
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parent[index] = child[0]
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else:
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node['nt'] = '+'
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child[1]['value'] = lslfuncs.neg(child[1]['value'])
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#TODO: Implement to transform 0-x into -x: elif child[0]['nt'] == 'CONST':
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rval['value'] = lslfuncs.neg(rval['value'])
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else:
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node['nt'] = '+'
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child[1] = {'nt':'NEG', 't':child[1]['t'], 'ch':[child[1]]}
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rnt = 'NEG'
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rval = child[1] = {'nt':rnt, 't':rval['t'], 'ch':[rval]}
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# rtype unchanged
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# Fall through to simplify it as '+'
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if nt == '+':
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# Tough one. Remove neutral elements for the diverse types,
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# and more.
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if optype == 'list' and not (ltype == rtype == 'list'):
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# Nothing to do with list + nonlist or nonlist + list.
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# FIXME: Not true. (list)"string" is a 5 byte saving vs.
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# [] + "string". Activating explicitcast forces the
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# conversion [] + (list)"string" -> (list)"string" which
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# is what we want here, but it is a loss for other types.
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# Further analysis needed.
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return
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if optype in ('vector', 'rotation'):
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# not much to do with vectors or quaternions either
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if lnt == 'CONST' and all(component == 0 for component in lval['value']):
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# Change <0,0,0[,0]>+expr -> expr
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parent[index] = rval
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elif rnt == 'CONST' and all(component == 0 for component in rval['value']):
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# Change expr+<0,0,0[,0]> -> expr
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parent[index] = lval
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return
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# Can't be key, as no combo of addition operands returns key
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# All these types evaluate as boolean False when they are
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# the neutral addition element.
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if optype in ('string', 'float', 'list'):
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if lnt == 'CONST' and not lval['value']:
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# 0 + expr -> expr
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# "" + expr -> expr
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# [] + expr -> expr
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parent[index] = self.Cast(rval, optype)
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elif rnt == 'CONST' and not rval['value']:
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# expr + 0 -> expr
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# expr + "" -> expr
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# expr + [] -> expr
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parent[index] = self.Cast(lval, optype)
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return
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# Must be two integers. This allows for a number of
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# optimizations. First the most obvious ones.
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if lnt == 'CONST' and lval['value'] == 0:
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parent[index] = rval
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return
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if rnt == 'CONST' and rval['value'] == 0:
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parent[index] = lval
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return
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# Remove parentheses if they enclose a NEG, to unhide their
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# operators. Precedence rules allow us.
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if lnt == '()' and lval['ch'][0]['nt'] == 'NEG':
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# (-expr) + expr -> -expr + expr
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lval = child[0] = lval['ch'][0]
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if rnt == '()' and rval['ch'][0]['nt'] == 'NEG':
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# expr + (-expr) -> expr + -expr
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rval = child[1] = rval['ch'][0]
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if lnt != 'CONST' != rnt:
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# Neither is const. Two chances to optimize.
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# 1. -expr + -expr -> -(expr + expr) (saves 1 byte)
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# 2. lvalue + -lvalue -> 0
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# There may be other possibilities for optimization,
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# e.g. (type)ident + -(type)ident but we only do lvalues
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# here. Note these are integers, no NaN involved.
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if lnt == rnt == 'NEG':
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node = {'nt':'+', 't':optype, 'ch':[lval['ch'][0], rval['ch'][0]]}
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node = {'nt':'()', 't':optype, 'ch':[node]}
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parent[index] = {'nt':'NEG', 't':optype, 'ch':[node]}
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return
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if lnt == 'NEG':
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# Swap to treat always as expr + -expr for simplicity.
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lnt, lval, rnt, rval = rnt, rval, lnt, lval
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if lnt == 'IDENT' and rnt == 'NEG' and rval['ch'][0]['nt'] == 'IDENT' \
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and lval['name'] == rval['ch'][0]['name']:
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# Replace with 0
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parent[index] = {'nt':'CONST', 't':optype, 'value':0}
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return
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if rnt == 'CONST':
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# Swap the vars to deal with const in lval always
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lval, lnt, rval, rnt = rval, rnt, lval, lnt
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if lval['value'] == -1:
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if rnt == 'NEG':
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parent[index] = {'nt':'~', 't':optype, 'ch':rval['ch']}
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else:
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parent[index] = {'nt':'~', 't':optype,
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'ch':[{'nt':'NEG', 't':optype, 'ch':[rval]}]}
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return
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if lval['value'] == -2:
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if rnt == 'NEG': # Cancel the NEG
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node = {'nt':'~', 't':optype, 'ch':rval['ch']}
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node = {'nt':'NEG', 't':optype, 'ch':[node]}
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parent[index] = {'nt':'~', 't':optype, 'ch':[node]}
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else: # Add the NEG
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node = {'nt':'NEG', 't':optype, 'ch':[rval]}
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node = {'nt':'~', 't':optype, 'ch':[node]}
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node = {'nt':'NEG', 't':optype, 'ch':[node]}
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parent[index] = {'nt':'~', 't':optype, 'ch':[node]}
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return
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if lval['value'] == 1:
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parent[index] = {'nt':'NEG', 't':optype,
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'ch':[{'nt':'~', 't':optype, 'ch':[rval]}]}
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return
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if lval['value'] == 2:
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node = {'nt':'NEG', 't':optype,
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'ch':[{'nt':'~', 't':optype, 'ch':[rval]}]}
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parent[index] = {'nt':'NEG', 't':optype,
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'ch':[{'nt':'~', 't':optype, 'ch':[node]}]}
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return
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# More than 2 becomes counter-productive.
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return
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elif nt == '<<' and child[1]['nt'] == 'CONST':
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# Transforming << into multiply saves some bytes.
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if child[1]['value'] & 31:
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@ -199,7 +362,18 @@ class optimizer(object):
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# Assume we already were there
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if 'ch' in defn:
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val = defn['ch'][0]
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if val['nt'] != 'CONST' or ident['t'] in ('list', 'key'):
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# TODO: We need some more analysis here.
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# As is, it "optimizes"
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# list A = [3,4,5,6,7,8,9];
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# list B = A;
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# to
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# list A = [3,4,5,6,7,8,9];
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# list B = [3,4,5,6,7,8,9];
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# which is counter-productive. But if we exclude lists,
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# we can't do this:
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# list A = [3,4,5,6,7,8,9];
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# list B = llList2List(A, 2, 3);
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if val['nt'] != 'CONST' or ident['t'] == 'key':
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return
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else:
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val = {'nt':'CONST', 't':defn['t'],
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@ -213,15 +387,20 @@ class optimizer(object):
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if nt == 'FNCALL':
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for idx in xrange(len(child)-1, -1, -1):
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self.FoldTree(child, idx)
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if 'fn' in self.symtab[0][node['name']]:
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fn = self.symtab[0][node['name']]['fn']
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if 'Fn' in self.symtab[0][node['name']]:
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if all(arg['nt'] == 'CONST' for arg in child):
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# Call it
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fn = self.symtab[0][node['name']]['Fn']
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value = fn(*tuple(arg['value'] for arg in child))
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if not self.foldtabs and isinstance(value, unicode) and '\t' in value:
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warning('WARNING: Tab in function result and foldtabs option not used.')
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return
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parent[index] = {'nt':'CONST', 't':node['t'], 'value':value}
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elif node['name'] == 'llGetListLength' and child[0]['nt'] == 'IDENT':
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# Convert llGetListLength(ident) to (ident != [])
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node = {'nt':'CONST', 't':'list', 'value':[]}
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node = {'nt':'!=', 't':'list', 'ch':[child[0], node]}
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parent[index] = {'nt':'()', 't':'list', 'ch':[node]}
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return
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if nt == 'PRINT':
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