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Get rid of label checks in some situations no longer supported

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Sei Lisa 2018-05-17 06:18:20 +02:00
parent 1d7142a698
commit 8f93386108
1 changed files with 11 additions and 49 deletions
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60
lslopt/lslfoldconst.py
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@ -107,7 +107,7 @@ class foldconst(object):
else:
idx += 1
def DoesSomething(self, node, labels = True):
def DoesSomething(self, node, labels = False):
"""Tell if a subtree does something or is just empty statements
(a pure combination of ';' and '{}'). Labels are the top level are
considered to do something if labels is True, and vice versa.
@ -120,7 +120,7 @@ class foldconst(object):
if node.nt == '{}':
for subnode in node.ch:
# Labels embedded in {} are not reachable. They do nothing.
if self.DoesSomething(subnode, labels = False):
if self.DoesSomething(subnode):
return True
else:
return True
@ -1526,8 +1526,8 @@ class foldconst(object):
self.FoldTree(child, 0)
# Test if the event is empty and SEF, and remove it if so.
if (not hasattr(node, 'scope') and not self.DoesSomething(child[0],
labels = False) and 'SEF' in self.events[node.name]
if (not hasattr(node, 'scope') and not self.DoesSomething(child[0])
and 'SEF' in self.events[node.name]
):
# Delete ourselves.
del parent[index]
@ -1602,33 +1602,15 @@ class foldconst(object):
if lslfuncs.cond(child[0].value):
self.FoldTree(child, 1)
self.FoldStmt(child, 1)
if len(child) == 3 and child[2].nt == '@':
# Corner case. The label is in the same scope as
# this statement, so it must be preserved just in
# case it's jumped to.
return
parent[index] = child[1]
return
elif len(child) == 3:
self.FoldTree(child, 2)
self.FoldStmt(child, 2)
if child[1].nt == '@':
# Corner case. The label is in the same scope as this
# statement, so it must be preserved just in case it's
# jumped to.
if not self.DoesSomething(child[2]):
del child[2]
return
parent[index] = child[2]
return
else:
# No ELSE branch, replace the statement with an empty one.
if child[1].nt == '@':
# Corner case. The label is in the same scope as this
# statement, so it must be preserved just in case it's
# jumped to.
parent[index] = child[1]
return
parent[index] = nr(nt=';', t=None, SEF=True)
return
else:
@ -1638,14 +1620,7 @@ class foldconst(object):
self.FoldTree(child, 2)
self.FoldStmt(child, 2)
# Check if it makes sense to swap if and else branches
# (but don't if the else branch is an elseless 'if'
# with a label, as it will be wrapped in {} making it
# become out of scope)
if (self.DoesSomething(child[2])
and (child[2].nt != 'IF'
or len(child[2].ch) == 3
or child[2].ch[1].nt != '@')
):
if (self.DoesSomething(child[2])):
# Check if we can gain something by negating the
# expression.
# Swap 'if' and 'else' branch when the condition has
@ -1661,8 +1636,7 @@ class foldconst(object):
child[0].nt = '^'
child[1], child[2] = child[2], child[1]
# Re-test just in case we swapped in the previous check.
if (not self.DoesSomething(child[2])
and child[1].nt != '@'):
if not self.DoesSomething(child[2]):
# no point in "... else ;" - remove else branch
del child[2]
if not self.DoesSomething(child[1]):
@ -1706,24 +1680,12 @@ class foldconst(object):
self.FoldCond(child, 0)
if child[0].nt == 'CONST':
# See if the whole WHILE can be eliminated.
if lslfuncs.cond(child[0].value):
# Endless loop which must be kept.
# Recurse on the statement.
self.FoldTree(child, 1)
self.FoldStmt(child, 1)
else:
if child[1].nt == '@':
# Corner case. The label is in the same scope as this
# statement, so it must be preserved just in case it's
# jumped to.
parent[index] = child[1]
else:
# Whole statement can be removed.
parent[index] = nr(nt=';', t=None, SEF=True)
if not lslfuncs.cond(child[0].value):
# Whole statement can be removed.
parent[index] = nr(nt=';', t=None, SEF=True)
return
else:
self.FoldTree(child, 1)
self.FoldStmt(child, 1)
self.FoldTree(child, 1)
self.FoldStmt(child, 1)
return
if nt == 'DO':