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Better optimization of (non-)equality comparisons.

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int != int was not properly optimized, because the != was transformed into the equivalent !(int == int) at an earlier stage. Fixed.

!(a ^ b) can be optimized to a == b, so do it.
This commit is contained in:
Sei Lisa 2018-03-23 16:04:18 +01:00
parent b284f95f98
commit a1f1f13739
1 changed files with 15 additions and 9 deletions
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24
lslopt/lslfoldconst.py
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@ -300,14 +300,12 @@ class foldconst(object):
parent[index] = child[0]['ch'][0]
return
if nt == 'NEG':
# bool(-a) equals bool(a)
parent[index] = child[0]
self.FoldCond(parent, index, ParentIsNegation)
return
if nt in self.binary_ops and child[0]['t'] == child[1]['t'] == 'integer':
if nt == '!=':
if (child[0]['nt'] == '==' and child[0]['ch'][0]['t'] == 'integer'
and child[0]['ch'][1]['t'] == 'integer'
):
# We have !(int == int). Replace with int ^ int or with int - 1
node = parent[index] = child[0] # remove the negation
child = child[0]['ch']
if child[0]['nt'] == 'CONST' and child[0]['value'] == 1 \
or child[1]['nt'] == 'CONST' and child[1]['value'] == 1:
# a != 1 -> a - 1 (which FoldTree will transform to ~-a)
@ -319,6 +317,14 @@ class foldconst(object):
self.FoldTree(parent, index)
return
if nt == 'NEG':
# bool(-a) equals bool(a)
parent[index] = child[0]
self.FoldCond(parent, index, ParentIsNegation)
return
if nt in self.binary_ops and child[0]['t'] == child[1]['t'] == 'integer':
if nt == '==':
if child[0]['nt'] == 'CONST' and -1 <= child[0]['value'] <= 1 \
or child[1]['nt'] == 'CONST' and -1 <= child[1]['value'] <= 1:
@ -702,7 +708,7 @@ class foldconst(object):
subexpr['ch'] = [subexpr['ch'][b], subexpr['ch'][a]]
parent[index] = subexpr
return
if snt == '!=':
if snt == '!=' or snt == '^':
subexpr['nt'] = '=='
parent[index] = subexpr
self.FoldTree(parent, index)