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Further generalize the < operator

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Use the node's min and max for both sides. Constants are just a special case where min = max = value.
This commit is contained in:
Sei Lisa 2024-05-07 00:56:40 +02:00
parent d2e3b9a3bd
commit c1c1b8c58d
1 changed files with 11 additions and 23 deletions
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34
lslopt/lslfoldconst.py
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@ -1331,38 +1331,26 @@ class foldconst(object):
SEF=True)
return
if child[0].nt == 'CONST' and child[1].SEF:
# when CONST >= second.max: always false
# when CONST < second.min: always true
rmin = self.getMin(child[1])
rmax = self.getMax(child[1])
if (rmax is not None
and not lslfuncs.less(child[0].value, rmax)
):
parent[index] = nr(nt='CONST', t='integer',
value=0, SEF=True)
return
if rmin is not None and lslfuncs.less(child[0].value, rmin):
parent[index] = nr(nt='CONST', t='integer',
value=1, SEF=True)
return
del rmin, rmax
if child[1].nt == 'CONST' and child[0].SEF:
# when first.max < CONST: always true
# when first.min >= CONST: always false
if child[0].SEF and child[1].SEF:
lmin = self.getMin(child[0])
lmax = self.getMax(child[0])
if lmax is not None and lslfuncs.less(lmax, child[1].value):
rmin = self.getMin(child[1])
rmax = self.getMax(child[1])
# when lmax < rmin: always true
if (rmin is not None and lmax is not None
and lslfuncs.less(lmax, rmin)
):
parent[index] = nr(nt='CONST', t='integer',
value=1, SEF=True)
return
if (lmin is not None
and not lslfuncs.less(lmin, child[1].value)
# when lmin >= rmax: always false
if (rmax is not None and lmin is not None
and not lslfuncs.less(lmin, rmax)
):
parent[index] = nr(nt='CONST', t='integer',
value=0, SEF=True)
return
del lmin, lmax
del lmin, lmax, rmin, rmax
# Convert 2147483647<i and i<-2147483648 to i&0
if (child[0].t == child[1].t == 'integer'